The inner one is redundant the outer one of course not.
Floor sqrt 1 0 8 x 1 2.
How do we define the floor of 2 31.
The outer one is not redundant because the square root of a number x only results in an integer if x is a square number.
And it has to be less than or maybe equal to 2 31 right.
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So which one do we choose.
2 is less than 2 31.
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Thanks to vinit for suggesting above optimization.
But 1 is also less than 2 31 and so is 0 and 1 2 3 etc.
Choose the greatest one which is 2 in.
Well it has to be an integer.
Floor of square root of x cannot be more than x 2 when x 1.
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